Find the particular solution of the differential equation `(1x^2)dy/dx=(e^(mtan^1 x)y)` , give that y=1 when x=0 Advertisement Remove all ads Solution Show Solution
++ 50 ++ (1-x^2)y''-2xy' 2y=0 y1=x 269664-(1-x^2)y''-2xy'+2y=0 y1=x
1 X 2 Y 2xy 2y 0 Power Series Solution Of Differential Equation Youtube
Answer (1 of 2) Ordinary Differential Equation x^2\,y'' xy' 2y = 0 \tag*{} has solution y_1 = x\,\sin(\ln x) \tag*{} To find a second solution we can use Reduction of order First we rewriteThis problem has been solved!
(1-x^2)y''-2xy'+2y=0 y1=x
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